Awater main made out of galvanized iron has an inner pipe diameter of 0.1 meters, an inlet pressure of 1000 kpa, outlet pressure of 500 kpa, water flow rate of 5 m3/min, and 10 90 degree elbows. what length galvanized iron line should be used to reach the desired outlet pressure?

Explanation:

The given data is as follows.

            Diameter = 0.1 m,           = 1000 kPa

            = 500 kPa

Change in pressure = 1000 kPa - 500 kPa = 500 kPa

Since, 1000 Pa = 1 kPa. So, 500 kPa will be equal to .

       Q = 5 = = 0.0833

It is known that Q =

where,           A = cross sectional area

                      V = speed of the fluid in that section

Hence, calculate V as follows.

                    V =

                        =

                        =

                        = 10.61 m/sec

Also it is known that Reynold's number is as follows.

                        Re =

                              =

                              = 1061032.954

As, it is given that the flow is turbulent so we cannot use the Hagen-Poiseuille equation as follows. Therefore, by using Blasius equation for turbulent flow as follows.

                            L =

                               = 90.328 m

Thus, we can conclude that 90.328 m length galvanized iron line should be used to reach the desired outlet pressure.

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