What is the fluid pressure (in units of ܲܽpascals) a distance 3.2 meters below the surface of lake superior?

fluid pressure = 132590 pascal

Explanation:

Fluid pressure can be  calculated by using following relation:

Where

Pb = fluid pressure at a distance of 3.2 m below from surface

Pa = fluid pressure at surface = atmospheric pressure = 101325 Pascal

g = gravitational constant = 9.8 m/sec2

Z = location depth from surface of lake

Therefore ,

1 Pascal = 1 Kg/(m.Sec)

       = 101325 + 132590 Pascal

       =  132590 pascal

2b2t

explanation:

2b2t