I’ll you : )
what is the mass of co2 produced when 100. g of butane, c4h10, is burned with excess oxygen,
according to the following chemical equation? (molar mass of c4h10 is 58.12 g/mol, molar mass of
co2 is 44.01 g/mol)
2 c4h10 (g) + 13 o2 (g) → 8 co2 (g) + 10 h20 (l)

The answer to your question is: 303g of CO2

Explanation:

Data

mass CO2 = ?

mass C4H10 = 100 g

MW C4H10 = 58.12 g

MW CO2 = 44.01 g

Solve this problem using rules of three

Reaction

                    2 C4H10 (g) + 13 O2 (g) → 8 CO2 (g) + 10 H20 (l)

                    2(58.12)       8(44.01)

                    100g              x

mass of CO2 produced = x = (100)(8)(44.01) / (2)(58.12)

                                          x = 35208 / 116.24

                                          x = 302.9 g ≈ 303 g of CO2

here is table 2-2:

country

percent of eligible voters that voted

rank

united states

44.9%

138

canada

60.1%

107

costa rica

84.6%

14

hungary

66.9%

82

japan

57.0%

118

egypt

27.7%

159

south africa

85.5%

10

ans is no, the data set cannot be plotted as a single circle graph