In a particular experiment, 2.50-g samples of each reagent are reacted. the theoretical yield of lithium nitride is g. molar mass of li is 6.94 g/mol. molar mass of n2 is 28.02 g/mol. molar mass of li3n is 34.83 g/mol.

4.18 g

Explanation:

The formula for the calculation of moles is shown below:

Given: For Li

Given mass = 2.50 g

Molar mass of Li  = 6.94 g/mol

Moles of Li  = 2.50 g / 6.94 g/mol = 0.3602 moles

Given: For

Given mass = 2.50 g

Molar mass of = 28.02 g/mol

Moles of = 2.50 g / 28.02 g/mol = 0.08924 moles

According to the given reaction:

6 moles of Li react with 1 mole of

1 mole of Li react with 1/6 mole of

0.3602 mole of Li react with mole of

Moles of that will react = 0.06 moles

Available moles of = 0.08924 moles

is in large excess. (0.08924 > 0.06)

Limiting reagent is the one which is present in small amount. Thus,

Li is limiting reagent.

The formation of the product is governed by the limiting reagent. So,

6 moles of Li gives 2 mole of

1 mole of Li gives 2/6 mole of

0.3602 mole of Li react with mole of

Moles of = 0.12

Molar mass of = 34.83 g/mol

Mass of = Moles × Molar mass = 0.12 × 34.83 g = 4.18 g

Theoretical yield = 4.18 g

sorry i was late, but i don't know what assignment your talking about, i'm in flvs as well, im in earth space science. but u are behind pace bc every class should be in the 3's or 4'

hey there!

mass = 6.75 g

volume =   9 cm³

therefore:

d = mass / volume

d   = 6.75 / 9

d = 0.7 g/cm³

answer b