Two different proteins x and y are dissolved in aqueous solution at 37 ∘c. the proteins bind in a 1: 1 ratio to form xy. a solution that is initially 1.00 mm in each protein is allowed to reach equilibrium. at equilibrium, 0.23 mm of free x and 0.23 mm of free y remain. what is kc for the reaction?

Kc = 1.4556 * 104

Explanation:

Two different proteins X and Y will bind in a 1:1 ratio to form XY

X + Y ⇔ XY

This means that for 1 mole X consumed, there will be 1 mole of Y consumed and 1 mole of XY produced

Both proteins X and Y have initially 1mM (= 0.001M)

if there is consumed x moles of protein X then there will also be consumed x moles of protein Y. As given the remaining concentration of both proteins X and Y is 0.23 mM (= 0.23 * 10^-3 M).

This means also that here will be produced x of the protein XY

x = 10^-3 - 0.23*10-3 = 7.7 * 10^-4 M

Kc = [XY] /[X][Y]

Kc = 7.7 * 10^-4 / ((0.23 * 10^-3)*(0.23 * 10^-3))

Kc = 1.4556 * 104

the answer is b & c i believe : )

the enthalpy of formation of water is given as -285.8kj/mol, which states that the enthalpy of formation is negative.

negative enthalpy of formation indicates that the heat is released during the reaction process. the heat is released from reaction to the surroundings the enthalpy is expressed with a negative sign with the energy given out in the reaction process.

the formation of water takes place by giving out heat which is -285.8 kj/mol.