One solution has a formula c (n) h (2n) o (n) if this material weighs 288 grams, dissolves in weight 90 grams, the solution will have a boiling point of 101.24 ° c. find the formula
the molecules of this substance when determining the kb value of water = 0.512 ° c / m and the atomic weight h = 1, c = 12 and o = 16.

Explanation:

The given data is as follows.

Boiling point of water ( = (100 + 273) K = 323 K,

Boiling point of solution ( = (101.24 + 273) K = 374.24 K

Hence, change in temperature will be calculated as follows.

                           = 374.24 K - 323 K

                           = 1.24 K

As molality is defined as the moles of solute present in kg of solvent.

            Molality =

Let molar mass of the solute is x grams.

Therefore,   Molality =

                        m =              

                          =

As,    

                       x =

                          = 1321.29 g

This means that the molar mass of the given compound is 1321.29 g.

It is given that molecular formula is .

As, its empirical formula is and mass is 30 g/mol. Hence, calculate the value of n as follows.

                n =

                   =

                   = 44 mol

Thus, we can conclude that the formula of given material is .

2b2t

explanation:

2b2t