Enter your answer in the provided box. calculate the number of g of co2 produced from the combustion of 5.24 mol of czhg. the balanced equation is: c3h2(g) + 502(g) → 3co2(g) + 4h2o(g). g co2

691.84g

Explanation:

I'm assuming that by CzHg, you mean C3H2

First, use the mole ratio in the equation to find the moles of CO2

n (CO2)= n ( C3H2) × 3

= 5.24 × 3

= 15.72

To find the mass of CO2 produced in grams, complete the following calculation

m= n × MM

where

m = mass

n= moles

MM= molecular mass

m= 15.72 × (12.01 +( 16×2))

m =691.8372

m= 691.84g

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