Aballoon is filled with 35.0 l of helium in the morning when the temperature is 303 degrees kelvin. by 3: 00 p. m., the temperature has risen to 333 degrees kelvin. what is the new volume of the balloon?

2882 l

38.5 l

31.8 l

65.0 l

The new volume of the balloon is 38.5 L

Explanation:

Step 1: Data given

Volume at the start = V1 = 35.0 L

Temperature at the start = T1 = 303 Kelvin

Volume by 3pm = TO BE DETERMINED

Temperature by 3pm = 333 Kelvin

Step 2: Calculate the new volume

Charles' gas law says

V1/T1  = V2/T2

V 1  is the initial volume and T1 is the initial temperature

V2 is the final volume and T2 is the final temperature

35 L / 303 Kelvin = V2 / 333 Kelvin

V2 = 35L * 333 Kelvin / 303 Kelvin

V2 = 38.47L ≈ 38.5 L

The new volume of the balloon is 38.5 L

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