Riley discovered pure gold has a density of 19.32 g/cm3.what would the volume for a piece of gold be if it had a mass of 318.97 g?

The volume for a piece of gold that has the mass of 318,67 g is 16,50cm3

Explanation:

Density = mass / volume

Volume = mass/ density

Volume = 318,97 g / 19,32 g/cm3 = 16,50cm3

The volume of a gold piece  is

Explanation:

Given:

Density of  pure gold,  

Mass of the gold piece,

To Find:

The volume for a piece of gold whose mass is  

Solution:

The formula for density is:

where,

D is density,

M is mass,  

V is volume.

The above formula can be rewriiten as

Substituting the values ,we get

Taking multiplicative inverse of density , we have

Result:

Thus the volume of gold piece weighing 318.97 g is

explanation: no but i do not usually comment

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :