5. a gas collected when the temperature is 298k and the pressure is 1.25 atm has a volume of 0.254l. calculate the volume when the temperature is lowered to 278k and the pressure is 1.67 atm. assume number of gas particles remain constant.

asked v2

0.177L

Explanation:

For this, we can use the combined gas law

(P1×V1)/T1=(P2×V2)/T2

where

P1 (initial pressure)= 1.25 atm

V1 ( initial volume)=0.254L

T1 (initial temperature in Kelvin)=298K

P2 ( final pressure)= 1.67 atm

V2 (final volume)=?

T2 (final temperature in Kelvin)=278K

Since we are trying to find the final volume, we can rearrange the above equation to make V2 the subject.

V2= (((P1×V1)/T1)×T2)/P2

V2= (((1.25×0.254)/298)×278)/1.67

V2=0.17736004501

V2= 0.177L

i think it's c. i'm not sure but i think so.