For each scenario, determine if the electron has absorbed energy or emitted energy,
an electron jumps from n = 3 to n = 1.
an electron jumps from n = 2 to n = 3.
an electron jumps from n = 1 to n = 2.
an electron jumps from n = 3 to n = 2.

1) emitted energy

2)absorbed energy

3)absorbed energy

4)emitted energy

Explanation:

I just got it right

1. Emitted

2. Absorbed

3. Absorbed

4. Emitted

Explanation:

With the above information in mind, it's just a matter of seeing if the initial n is higher or lower than the final n.

first, consult an activity series chart to determine if al is more reactive than fe. it is, so it will replace the fe. now, one can continue with the problem.

next, make sure you have a correctly balanced equation.

3feo + 2al ==> 3fe + al2o3

now, determine which reactant (feo or al) is in limiting supply.

moles feo present = 125 g x 1 mole/71.8 g = 1.74 moles

moles al present = 25.0 g x 1 mole/26.98 g = 0.927 moles

since from the balanced equation, it take 3 mol feo for every 2 mol al, al will be limiting.

you can determine this simply by dividing moles of each by their coefficient in the balanced equation. for example: 1.74/3 = 0.58 and 0.927/2 = 0.464. al is less, so it is limiting.

finally, using the stoichiometry in the balanced eq. determine mass of fe that can be produced from 0.927 moles of al.

0.927 moles al x 3 moles fe/2 moles al x 55.8 g/mole = 77.6 g