How many milliters of a 0.171 solution contains 1.00 g of nacl

:  Molar mass of NaCl: 35.4+22.9 = 58.3 g/mol

X milliliters (=X/1000 liters) of a 0.171M solution contain 0.171*X/1000 moles of NaCl.
0.171*X/1000 moles of NaCl = 58.3*0.171*X/1000 g = 1 g (as given)
58.3*0.171*X/1000 = 1
X = 100.3

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