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Each step in the process below has 80% yield.
ch4+4cl2 > ccl4+4hcl
ccl4+2hf --> ccl2f2+2hcl
the ccl4 formed in the first step is used as a reactant in the second step.
if 2.00 mol of ch4 reacts, what is the total amount of hcl produced? assume that cl2 and hf are present in the excess.
explain
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You know the right answer?
Each step in the process below has 80% yield.
ch4+4cl2 > ccl4+4hcl
ccl4+2hf -->...
ch4+4cl2 > ccl4+4hcl
ccl4+2hf -->...
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