Dinitrogen monoxide or laughing gas (n2o) is used as a dental anesthetic and as an aerosol propellant. how many moles of n2o are present in 12.6 g of the compound? how many molecules of n2o are present in 12.6 g of the compound? [use molar masses: n, 14.01 g/mol, o, 16.00 g/mol]

In 12.6g of there are 0.29 moles of and molecules of

Explanation:

First you should find the molar mass of the :

Then you should write the conversion factor using the molar mass:

So, there are 0.29 moles of in 12.6g of .

Finally to find the number of molecules, you should use the Avogadro´s number:

There are moles of in 12.6g of

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.

the answer is b & c i believe : )