137 g of barium reacts with g iodine to produce 391 g barium iodide
group of answer choices

391

254

534

137

Option (b) is the correct answer.

Explanation:

According to law of conservation of mass, mass can neither be created nor it can be destroyed. It can only be changed from one form to another.

For example,  when 137 g of barium reacts with x grams of iodine to produce 391 g barium iodide.

Then mass of iodine will be calculated as follows.

               Total mass of reactants = total mass of products

                          137 g + x = 391 g

                             x = 391 g - 137 g

                                = 254 g

Thus, we can conclude that 137 g of barium reacts with 254 g iodine to produce 391 g barium iodide.

2h2o2--> 2h2o + o2

this reaction is of the spontaneous decomposition of hydrogen peroxide down into water and oxygen.

add 2 molecules of hydrogen peroxide and 2 molecules of water. since oxygen is naturally diatomic, the total number of atoms of each element is now the same on both sides of the equation so it is balanced.

this may not be entirely correct but let me know.

the electron configuration that you gave me has 16 electrons ergo it has 16 protons ergo it is the element sulfur.