If an athlete expends 2965 kj/h, how long does she have to play to work off 1.00 lb of body fat? note that the nutritional calorie (calorie) is equivalent to 1 kcal, and one pound of body fat is equivalent to about 4.10 × 103 calories.

hours?

5.78 h

Explanation:

To answer this problem first we convert 2965 kJ/h to kcal, and then we convert that value into nutritional calories per hour ( Calories/h), as follows:

2965 kJ/h * 708.635 Calories/h

Then we divide 4.10 x 10³ Calories by that value, in order to calculate how many hours it would take to burn off that many Calories (which are equal to 1.00 lb of body fat):

4.10 x 10³ Calories ÷ (708.635 Calories/h) = 5.78 h

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o