Specific heat material copper aluminum gold pyrex specific heat (j/g °c) 0.385 0.902 0.129 0.75 material water ice olive oil air specific heat (1/g °c) 4.18 2.01 2.38 1.00 if the same amount of heat was applied to a vessel containing 100.0 g of water and 100.0 g of olive oil, which would get hotter? why? if you had a 1.0 kg pot made of each metal, which pot would allow you to heat water to boiling more quickly? why? how much heat would it take to raise the temperature of 100.0 g of water from 20.0°c to 100.0 °c? (ignore the pot)

Explanation:

Since,     q =

So, larger is the specific heat of a substance less will be the change in its temperature.

Therefore, olive oil has less specific heat as compared to water. This means that olive oil would get hotter.

As a result, water present in gold will heat readily.

              q =

Therefore, calculate the amount of heat required by the water as follows.

                 q =

                    =

                    = 33440 J

or,                 = 33.44 kJ               (as 1 kJ = 1000 J)

Thus, 33.44 kJ heat would it take to raise the temperature of 100.0 g of water from to .

when [oh-] is 10-5  m, and [h3o+] is 10-9  m, the poh is 5 and ph is 9. again in both cases the sum of ph and poh is 14. however, the hydrogen ion concentration is not always going to be equal to exactly 1 x 10 raised to a negative number. for example, we skipped over the value of 2.0 x 10-7.

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer