The enthalpy of fusion for benzene (c6h6, 78.0 g/mol) is 127.40 kj/kg, and its melting point is 5.5°c. what is the entropy change when 1 mole of benzene melts at 5.5°c? (show all unit conversions and write out all equations)

35.662 J/K is the entropy change when 1 mole of benzene melts at 5.5°C

Explanation:

The enthalpy of fusion for benzene =

Molar mass of benzene = 78.0 g/mol

Or can be written as 1 mole of benzene = 78.0 g

1 g of benzene  =

= 127.40 kJ/kg=127.40 kJ/1000 g (1kg = 1000 g)

= 9.9372 kJ/mol = 9937.2 J /mol

The entropy change when 1 mole of benzene melts at 5.5°C:

T = 5.5°C = 278.65 K

answer: option (b) is the correct answer.

explanation:

a covalent bond is formed by sharing of electrons. whereas polarity arises due to difference in electronegativity of two atoms.

therefore, more is the electronegativity of an atom which combines with the titanium, more readily it will induce a partial positive and negative charge.

thus, out of the given options fluorine is most electronegative and has an incomplete octet. therefore, it will readily combine with titanium to share the electrons and complete its octet.  

c. heat could easily travel through the molecules in the air and escape/enter the flask. removing the air slows down the heat transfer.