The balmer-rydberg equation was derived from the observations of the spectral lines from the hydrogen emission spectrum. it relates the beginning and ending energy states of an electronic transition to the difference in energy between the two states.

δe = −2.179 ✕ 10^−18 j

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how much energy, in joules, is needed to excite an electron from the n=2 energy level to the n=5 energy level? report your response to three (3) significant figures.
in j
what wavelength of light, in meters, is needed to excite an electron from the n=2 energy level to the n=5 energy level? report your response to three (3) significant figures.
in m

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally

a). in this case, dh> 0 and sd> 0. if t becomes larger, the term "-tds" will become more negative. at some point, it is possible that -dts will be more negative than the dh is positive, and the reaction will become spontaneous. this is probably the correct answer, but you should look at all of the other possibilities and make sure of that.