For the reaction fe3o4(s) + 4h2(g) --> 3fe(s) + 4h2o(g)

h° = 151.2 kj and s° = 169.4 j/k

the equilibrium constant for this reaction at 328.0 k is

Answer : The value of equilibrium constant for this reaction at 328.0 K is

Explanation :

As we know that,

where,

= standard Gibbs free energy  = ?

= standard enthalpy = 151.2 kJ = 151200 J

= standard entropy = 169.4 J/K

T = temperature of reaction = 328.0 K

Now put all the given values in the above formula, we get:

The relation between the equilibrium constant and standard Gibbs free energy is:

where,

= standard Gibbs free energy  = 95636.8 J

R = gas constant  = 8.314 J/K.mol

T = temperature  = 328.0 K

K = equilibrium constant = ?

Now put all the given values in the above formula, we get:

Therefore, the value of equilibrium constant for this reaction at 328.0 K is