Consider the reaction: 2brf3(g) --> br2(g) + 3f2(g)

using standard absolute entropies at 298k, calculate the entropy change for the system when 1.62 moles of brf3(g)react at standard conditions.

Answer : The entropy change of reaction for 1.62 moles of reacts at standard condition is 217.68 J/K

Explanation :

The given balanced reaction is,

The expression used for entropy change of reaction is:

where,

= entropy change of reaction = ?

n = number of moles

= standard entropy of formation

= 245.463 J/mol.K

= 202.78 J/mol.K

= 292.53 J/mol.K

Now put all the given values in this expression, we get:

Now we have to calculate the entropy change of reaction for 1.62 moles of reacts at standard condition.

From the reaction we conclude that,

As, 2 moles of has entropy change = 268.74 J/K

So, 1.62 moles of has entropy change =

Therefore, the entropy change of reaction for 1.62 moles of reacts at standard condition is 217.68 J/K

the electronic configuration of an atom with eight electrons is 1s²2s²2p⁴. the orbital diagrams are shown in the figure.

as per the hunds rule:

1. electrons tend to avoid being in the same orbital as per as practicable.

2. electrons in different orbitals of the same energy will have their spin parallel.

this can be illustrated from the multiplicity of the orbitals of the atom. as there are four electrons in the p orbital and p orbital has 3 sub-shells. the electrons can be fed in different ways as shown in the figure but the correct orbital diagram will be as per the hunds rule.

- lead + phosphoric acid = hydrogen + lead(ii) phosphate