Compute a value for dab for a system of argon (a) and oxygen (b) at 294 k and atmospheric pressure.

DAB = 1.921 E-5 m²/s

Explanation:

DAB = ((1 E-7 T∧(1.75))*((1/MA + 1/MB)∧(1/2)))/[ P*(∑vA)∧(1/3) + (∑vB)∧(1/3)]²Fuller et All.

∴ ∑vA = 16.1 m³/Kgfrom literature

∴ ∑vB = 16.6 m³/Kgfrom literature

∴ T = 294 K

∴ P = 1 atm

∴ MA = 39.948  Kg/Kmol

∴ MB = 32 Kg/Kmol

⇒ DAB = ((2.087 E-3)*(0.2372))/[1*(25.766)]

⇒ DAB = 1.921 E-5 m²/s

16

explanation:

the marks go by 4s

you need to have a picture of the atom that way we can answer it