The density of pure gold is 19.3g/cm3. what is the volume of 1.00 g of pure gold?

Volume of 1g of pure gold

Given;

Density of a pure gold=19.3

Mass of a pure gold =1g

To find:

Volume of 1g of pure gold

Solution:

According to the formula,

Density= Mass/Volume

Where =density of pure gold

           m=mass of pure gold

          v=volume of pure gold

From the above equation volume can be calculated as

Substitute the values of mass and density value in the above equation

Result:

Thus the volume of 1g of pure gold is

answer: -

reaction:

na + cl ⇌ nacl

balanced chemical equation:

na + 2cl ⇌ nacl2

sodium + clorine goes to form sodium chloride (table salt).

the product is nacl2.

and the reactants are na and cl.

(note: if you don’t know what ⇌ means, read below: -

⇌(double head arrow) means reversible reaction).

i just calculated it all out, and not including weekends, and all the different days off. as of this school year (2018-2019) students are spending 2198 hours in school this year