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Chemistry, 05.10.2019 13:00 edsimms21111

Examine the isotopes.

hydrogen-3 (3h)
carbon-14 (14c)
oxygen-16 (16o)

which one or more of these isotopes would be more likely to undergo nuclear decay, and why?

hint: hydrogen's atomic number = 1; carbon's atomic number = 6; oxygen's atomic number = 8

oxygen-16 would be more likely to decay, because its neutrons and protons are equal.
oxygen-16 would be more likely to decay, because it has the largest atomic mass.
carbon-14 and oxygen-16 would be more likely to decay, because their atomic numbers are higher.
carbon-14 and hydrogen-3 would be more likely to decay, because their neutrons and protons are not equal.

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You know the right answer?
Examine the isotopes.

hydrogen-3 (3h)
carbon-14 (14c)
oxygen-16 (16o)
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