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Chemistry, 06.10.2019 09:02 oliviaschmitt0

The blood alcohol (c2h5oh) level can be determined by titrating a sample of blood plasma with an acidic potassium dichromate solution, resulting in the production of cr3+(aq) and carbon dioxide. the reaction can be monitored because the dichromate ion (cr2o72−) is orange in solution, and the cr3+ ion is green. the unbalanced redox equation is the following. cr2o72−(aq) + c2h5oh(aq) → cr3+(aq) + co2(g) if 31.91 ml of 0.0613 m potassium dichromate solution is required to titrate 33.8 g of blood plasma, determine the mass percent of alcohol in the blood.

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