To set up the first equilibrium, place ~5 ml of water in a test tube add a couple drops of methyl violet indicator. record the initial color of the solution. choose a reagent that you believe will force the equilibrium towards the other side of the equation (cause the solution to change colors). available reagents will include hcl, hno3, hc2h3o2, naoh and nh3. add you selected reagent one drop at a time (with mixing) until a color change is observed. if your reagent does not cause the desired change, choose another reagent and repeat until the correct reagent is found. after you have changed the color of the solution, choose a reaction that you believe will reestablish the original color. add the selected reagent drop by drop (with mixing) until the desired change is achieved.

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explanation:

because it is

use quiz let it tells you all the answers thats what i use

answer: - first one is the correct answer. .

explanations: - potassium sulfide is and cobalt(ii) chloride is .

charge on k is +1, charge on s is -2, charge on co is +2 and charge on cl is -1.

in a double replacement reaction the ion exchange takes place. in general the reaction looks like:

if one of the product is insoluble as per solubility rules then a precipitate of it is formed.

when we mix the aqueous solutions of potassium sulfide and cobalt(ii) chloride then chloride ion goes with potassium ion and sulfide ion goes with cobalt ion and the balanced equation is written as:

k and cl has equal charges, similarly co and s has equal charges and hence no subscripts are used for the product side.

as per the solubility rules, cos is insoluble and so it's precipitate is formed.

looking at the given choices, first choice is correct.