Chemistry, 06.10.2019 11:30 Rosalycarlite5358

Balance the equations by inserting coefficients as needed.

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Answer from: Kimbeeeerly7631

Answer :

(1) The balanced chemical reaction will be,

$2ZnO+C\rightarrow 2Zn+CO_2$

(2) The balanced chemical reaction will be,

$2SO_2+O_2\rightarrow 2SO_3$

Explanation :

Balanced chemical reaction : It is defined as the reaction in which the number of atoms of individual elements present on reactant side must be equal to the product side.

If the amount of atoms of each type on the left and right sides of a reaction differs then to balance the equation by adding coefficient in the front of the elements or molecule or compound in the chemical equation.

The coefficient tell us about that how many molecules or atoms present in the chemical equation.

Equation 1 :

The unbalanced chemical reaction is,

$ZnO+C\rightarrow Zn+CO_2$

This reaction is an unbalanced chemical reaction because in this reaction number of oxygen atoms are not balanced.

In order to balance the chemical equation, the coefficient '2' put before the $ZnO\text{ and }Zn$ and we get the balanced chemical equation.

The balanced chemical reaction will be,

$2ZnO+C\rightarrow 2Zn+CO_2$

Equation 2 :

The unbalanced chemical reaction is,

$SO_2+O_2\rightarrow SO_3$

This reaction is an unbalanced chemical reaction because in this reaction number of oxygen atoms are not balanced.

In order to balance the chemical equation, the coefficient '2' put before the $SO_2\text{ and }SO_3$ and we get the balanced chemical equation.

The balanced chemical reaction will be,

$2SO_2+O_2\rightarrow 2SO_3$

Answer from: Quest

n2(g) + 3h2-> 2nh3(g) this is the balanced equation

note the mole ratio between n2, h2 and nh3. it is 1 : 3 : 2 this will be important.

moles n2 present = 28.0 g n2 x 1 mole n2/28 g = 1 mole n2 present

moles h2 present = 25.0 g h2 x 1 mole h2/2 g = 12.5 moles h2 present

based on mole ratio, n2 is limiting in this situation because there is more than enough h2 but not enough n2.

moles nh3 that can be produced = 1 mole n2 x 2 moles nh3/mole n2 = 2 moles nh3 can be produced

grams of nh3 that can be produced = 2 moles nh3 x 17 g/mole = 34 grams of nh3 can be produced

note: the key to this problem is recognizing that n2 is limiting, and therefore limits how much nh3 can be produced.

Answer from: Quest

1. they vary with a higher number because boiling is way hotter than melting

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Balance the equations by inserting coefficients as needed.

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