N2(g) + 3 h2(g) > 2 hn3(g) (blanced)

if 5.42 g of nitrogen are reacted with 5.42 g of hydrogen gas, which of the reactants is the limiting reactant?

molar mass of n2 = 28.02 g/mol
molar mass of h2 = 2.02 g/mol
molar mass of nh3 = 17.04 g/mol

N₂

Explanation:

The limiting reactant is the one that gives the smaller amount of product.

Assemble all the data in one place, with molar masses above the formulas and masses below them.

M_r:   28.02  2.02     17.04  

             N₂ + 3H₂ ⟶ 2NH₃

m/g:    5.42  5.42

1. Calculate the moles of each reactant  

2. Identify the limiting reactant  

Calculate the moles of NH₃ we can obtain from each reactant.

From N₂:  

The molar ratio of NH₃:N₂ is 2:1.

From H₂:

The molar ratio of NH₃:H₂ is 3:2.  

N₂ is the limiting reactant, because it gives the smaller amount of NH₃.

the answer to your question is c