For the following chemical reaction, given 2.5 gram mgso4 with an excess of ba(no3)2, calculate the theoretical mass of baso4 precipitate produced from the reaction (in grams). the following conceptual plan is designed to you convert the mass of the limiting reactant (mgso4) to the mass of the desired product (baso4).

The answer to your question is:  4.9 g of BaSO4

Explanation:

Data

MgSO4 = 2.5 g

Ba(NO3)2 = excess reactant

BaSO4 = ?

Reaction

                  MgSO4   +    Ba(NO3)2      ⇒     BaSO4   +    Mg(NO3)2

MW MgSO4 = 24 + 32 + 64

                    = 120 g

MW BaSO4 = 137 + 32 + 64

                    = 233 g

                  120 g of MgSO4  233g of BaSO4

                  2.5 g                       x

                  x = 4.9 g of BaSO4

idk i’m struggling too

lol for the pointsss