Asolution of sodium hydroxide is standardized against potassium hydrogen phthalate. from the following data, calculate the molarity of naoh solution. mass of khp used: 0.4536 g buret reading before titration: 0.23 ml buret reading at the end point: 31.26 ml

0.7158 Mol/L

Explanation:

KHC8H4O4 + NaOH → H2O + KNaC8H4O4

KHC8H4O4 molar mass = 204.2212 g/mol

0.4536 g of KHC8H4O4 = 2.221 mMol (10^-3 mol)

volume = 31.26 mL - 0.23 mL = 31.03 mL

NaOH concentration = 2.221 mMol/31.03 mL = 2.221 Mol/31.03 L = 0.7158 Mol/L

when [oh-] is 10-5  m, and [h3o+] is 10-9  m, the poh is 5 and ph is 9. again in both cases the sum of ph and poh is 14. however, the hydrogen ion concentration is not always going to be equal to exactly 1 x 10 raised to a negative number. for example, we skipped over the value of 2.0 x 10-7.