What is the correct equilibrium constant expression for the following heterogeneous equilibrium? 4hcl (g) + o2 (g) ⇄ 2h2o (l) + 2cl2 (g) view available hint(s) what is the correct equilibrium constant expression for the following heterogeneous equilibrium?
4hcl (g) + o2 (g) ⇄ 2h2o (l) + 2cl2 (g)
kc=[cl2]/[hcl][o2] kc=[hcl]4[o2]/[cl2]2
kc=[cl2]2[h2o]2/[hcl]4[o2]
kc=[cl2]2/[hcl]4[o2]

Kc=[Cl2]2/[HCl]4[O2]

Explanation:

For determinate the equillibrium constant, water and pure susbtances are not taken account on the calculus. In this case, water are present in the equation, so we have to remove it in the Kc determination.

i don t now

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer