The effective molar mass of ashes has units of grams of ashes per mole of base provided. the mass of the ashes in the experiment is given, 20.4 g. the rest of the work involves determining the amount of base provided, in moles. we will first determine the moles of base used in the titration. what volume of acid was used in the experiment?

може ли да зареждате повече информация, моля

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o