Chemistry, 09.10.2019 03:00 destiny465

H2so4 is an unusual diprotic acid in that the first dissociation is considered strong, but the second dissociation is weak. therefore, h2so4 only has ka2 = 1.2x10−2. consider an aqueous solution containing 0.010 m h2so4. calculate the concentration of so42− ions in this solution. calculate the concentration of hso4− ions in this solution. calculate the concentration of h3o+ ions the solution. enter each of your answers to two significant figures. do not use scientific notation.

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Answer from: koboshy23

Explanation:

As it is given that the initial concentration of sulfuric acid is 0.010 M.

Hence, the ICE table for first dissociation of sulfuric acid is as follows.

$H_{2}SO_{4} + H_{2}O \rightleftharpoons HSO^{-}_{4} + H_{3}O^{+}$

Initial: 0.010 0 0

Change: -0.010 +0.010 +0.010

Equilibrium: 0 0.010 0.010

When second dissociation of sulfuric acid occurs which is partial then the ICE table will be as follows.

$HSO^{-}_{4} + H_{2}O \rightleftharpoons SO^{2-}_{4} + H_{3}O^{+}$

Initial: 0.010 0 0.010

Change: -x +x +x

Equilibrium: 0.010 - x x 0.010 + x

Since, it is given that $K_{a} = 1.2 \times 10^{-2}$ . Hence, formula for $K_{a}$ is as follows.

$K_{a} = \frac{[SO^{2-}_{4}][H_{3}O^{+}]}{[HSO^{-}_{4}]}$

$1.2 \times 10^{-2} = \frac{x(0.010 + x)}{(0.010 - x)}$

$0.0012 \times (0.010 - x) = x(0.010 + x)$

$0.00012 - 0.012x = x^{2} + 0.010x$

x = 0.0045

Hence, by using the equilibrium concentrations from the table and value of x we get the following.

$[SO^{2-}_{4}]$ = x,

= 0.0045 M

$[HSO^{-}_{4}]$ = 0.010 - x

= 0.010 - 0.0045

= 0.0055 M

$[H_{3}O^{+}]$ = 0.010 + x

= 0.010 + 0.0045

= 0.0145 M

Answer from: Quest

The answer is 4 i don't know if its right let me see.

Answer from: Quest

ca has a crystalline lattice with positive ions (since it is a metal, metals are positively charged) and electrons flow freely in its structure since the ca atoms have a large nuclear radius so the electrons are not tightly held, therefore the electrons can flow freely since they are not being highly attracted by the nucleus. moreover, one of the properties of metals are that they are conductors of electricity, thus proving ca is the element.

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H2so4 is an unusual diprotic acid in that the first dissociation is considered strong, but the secon...