Matt is touring a nation in which coins are issued in two amounts, 2¢ and 5¢, which are made of iron and copper, respectively. if matt has ten iron coins and ten copper coins, how many different sums from 1¢ to 70¢ can he make with a combination of his coins?

It can be made 66 combinations.

Explanation:

Total amount of possibilities= 10×5¢+10×2¢=70¢

The first combination 1¢ cannot be made because 2¢ is not divisible.

The second combination is 2¢. (Possible)

The third combination 3¢ cannot be made for the same reason.

There are no possible combinations for 1¢ and 3¢.

The same happens with 67 and 69.

For example:

66¢= 10×5¢+8×2¢

Next combination will be:

68¢= 10×5¢+9×2¢

And finally:

70¢= 10×5¢+10×2¢

So there are 4 combinations that are not possible.

The total amount of possible combinations are:

70-4=66 combinations

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.

if you're asking what comes out, it's steam.