At 1173 k, keq = 0.0108 for the following reaction: caco3(s) ⇄ cao(s) + co2(g) the reaction takes place in a 10.0 l vessel at 1173 k. if a mixture of 15.0 g caco3, 15.0 g cao, and 4.25 g co2 is allowed to approach equilibrium, what will happen to the amount of caco3? group of answer choices
- it will remain the same
- it will increase
- not enough information is provided to answer this question
- it will decrease

The amount of calcium carbonate will increase.

Explanation:

K is the constant of a certain reaction when it is in equilibrium, while Q is the quotient of activities of products and reactants at any stage other than equilibrium of a reaction.

Equilibrium constant of the reaction =

Concentration of

Concentration of

Concentration of

This means that equilibrium will move in backward direction by which amount of calcium carbonate will increase.

the old alchemists made significant contributions to science even though there starting premises were off a bit. their conclusions after failure would steer them into better directions for investigation. science is no more than close observation and the initial mistakes result in rethinking and retrying experiments.