Assume that you have 1, 2, 5, and 10 ml pipets and a 25 ml volumetric flask only. describe in detail how you would prepare a solution with a concentration near 0.100 m from a 0.650 m stock solution using the glassware listed above. calculate the final concentration of the diluted solution (it won't be exactly 0.100 m). it should be within 10% of 0.100 m. ( see the lab skills for the accuracy on volumetric pipets and flasks.)

Explanation:

The given data is as follows.

      = 25 ml,           = 0.10 M

      = x ml = ,         = 0.650 M

It is known that relation between molarity and volume of two solutions is as follows.

        =

        =

                x = 0.00385 L

or,                = 3.85 ml

Since, this volume is closest to 4 ml so, we have to use a 2 ml pipette two times and then we have to put it in a 25 ml volumetric flask.

Hence, calculate the overall concentration as follows.

                    =

                      =    

                        x = 0.104 M

Therefore, it is about 3.8% error that is lower than the required error.

b. is the answer hoped i        

it can be observed without changing the identity of the object.

it depends on what substance you're talking about as well as many other factors. in quantum mechanics, the observation of particles affects the observers ability to measure certain properties. for example: you can know the velocity of a particle, but you can't know it's position; or you can know it's position, but not it's velocity. it's like trying to find out where a grain of sand is by throwing other grains of sand at it. once you find out where it is, it's been moved. it's also like trying to find an answer to the question of whether or not a tree falling in a forest makes a sound if nobody is there to hear it. paradoxically, the only way to find out is to be there and hear it.