2.00 mol of h2(g) and 1.00 mol of i2(g) are placed in a 1.00 l container, and they react to form hi(g). at equilibrium, it is found that 1.80 moles of hi(g) are present in the container. calculate k for the reaction: h2(g) i2(g) ⇄ 2 hi(g)

The answer to your question is:         k = 1.62

Explanation:

Data

H2(g) = 2.00 mol

I2 (g) = 1.00 mol

HI (g) = 1.80 mol

K = ?

Reaction              H2(g)  +    I2(g)     ⇄     2 HI(g)

Formula

Substitution

                                    k =

                                    k = 1.62

answer: h+ its less than oh

explanation: