Calculate the mass percent of cl in freon -112 (c2 cl4 f2), a cfc refrigerant

The answer to your question is:  69.6 %

Explanation:

Freon -112 (C₂Cl₄F₂)

MW = (12 x 2) + (35.5 x 4) + (19 x 2)

      = 24 + 142 + 38

      = 204 g

                       204 g of C₂Cl₄F₂    100%

                       142 g                       x

                      x = (142 x 100 ) / 204

                      x = 69.6 %

i think it is true since you can test the answer and can use observations to complete it.

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