One enzyme-catalyzed reaction in a biochemical cycle has an equilibrium constant that is 10 times the equilibrium constant of a second reaction. if the standard gibbs energy of the former reaction is −300 kj mol−1, what is the standard reaction gibbs energy of the second reaction?

Explanation:

The relation between standard Gibbs energy and equilibrium reaction is shown below as:

R is Gas constant having value = 0.008314 kJ / K mol

Given temperature, T = 300 K (Source Original)

Given,

So,

Also,

K₁ = 10*K₂

K₂ = 0.1 K₁

So,

bcde is the incorrect answer it is a

hey there!

mass = 6.75 g

volume =   9 cm³

therefore:

d = mass / volume

d   = 6.75 / 9

d = 0.7 g/cm³

answer b