Achemist needs to determine the concentration of a sulfuric acid solution by titration with a standard sodium hydroxide solution. he has a 0.1790 m standard sodium hydroxide solution. he takes a 25.00 ml sample of the original acid solution and dilutes it to 250.0 ml. then, he takes a 10.00 ml sample of the dilute acid solution and titrates it with the standard solution. the endpoint was reached after the addition of 18.07 ml of the standard solution. what is the concentration of the original sulfuric acid solution?

The concentration of original sulfuric acid solution is 1.62 M

Explanation:

Let the original concentration of sulfuric acid be 'x' M

To calculate the molarity of the diluted solution, we use the equation:

where,

are the molarity and volume of the concentrated sulfuric acid solution

are the molarity and volume of diluted sulfuric acid solution

We are given:

Putting values in above equation, we get:

Now, to calculate the concentration of acid, we use the equation given by neutralization reaction:

where,

are the n-factor, molarity and volume of acid which is

are the n-factor, molarity and volume of base which is NaOH.

We are given:

Putting values in above equation, we get:

Hence, the concentration of original sulfuric acid solution is 1.62 M

the answer for sodium is 0.186

the answer for rubidium is 0.251

1.solid

2.carbon dioxide

3.helium