Enter your answer in the provided box. a person's blood alcohol (c2h5oh) level can be determined by titrating a sample of blood plasma with a potassium dichromate solution. the balanced equation is 16h (aq) 2cr2o72−(aq) c2h5oh(aq) → 4cr3 (aq) 2co2(g) 11h2o(l) if 35.46 ml of 0.05961 m cr2o72− is required to titrate 26.60 g of plasma, what is the mass percent of alcohol in the blood

The mass percent of alcohol in blood is 0.183 %

Explanation:

To calculate the moles for given molarity, we use the equation:

Molarity of solution = 0.05961 M

Volume of solution = 35.46 mL = 0.03546 L   (Conversion factor:  1 L = 1000 mL)

Putting values in above equation, we get:

The given chemical reaction follows:

By Stoichiometry of the reaction:

2 moles of dichromate ions react with 1 mole of ethanol.

So, of dichromate ions will react with =

Moles of ethanol =

Molar mass of ethanol = 46.07 g/mol

Putting values in above equation, we get:

Mass of blood plasma = 26.60 g

Mass of ethanol = 0.0488 g

Putting values in above equation, we get:

Hence, the mass percent of alcohol in blood is 0.183 %