Container a holds 717 ml of an ideal gas at 2.20 atm. container b holds 124 ml of a different ideal gas at 4.20 atm. container a and container b are glass spheres connnected by a tube with a stopcock. container a is larger than container b. if the gases are allowed to mix together, what is the resulting pressure?

2.4949 atm

Explanation:

For Container A :  

Pressure = 2.20 atm

Temperature = T K

Volume = 717 mL = 0.717 L (1 mL = 0.001 L)

Using ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

2.20 atm × 0.717 L = n × 0.0821 L.atm/K.mol × T K  

⇒n = 19.2132 / T moles

For Container B :  

Pressure = 4.20 atm

Temperature = T

Volume = 124 mL = 0.124 L (1 mL = 0.001 L)

Using ideal gas equation as:

PV=nRT

Applying the equation as:

4.20 atm × 0.124 L = n × 0.0821 L.atm/K.mol × 298 K

⇒n = 6.3435 / T moles

Total moles = 19.2132 / T moles + 6.3435 / T moles = 25.5567 /T moles

Total Volume = 717 + 124 mL  =  841 mL = 0.841 L

Temperature = T

Using ideal gas equation as:

PV=nRT

Applying the equation as:

P × 0.841 L = 25.5567 /T × 0.0821 L.atm/K.mol × T

⇒Total P = 2.4949 atm

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

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