How many milliliters of 11.5 m hcl(aq) are needed to prepare 855.0 ml of 1.00 m hcl(aq)?

The answer to your question is:   V1 = 74.35 ml

Explanation:

Data

Volume 1 = V1 = ?

Concentration 1 = C1 = 11.5 M

Volume 2 = V2 = 855 ml

Concentration  2 = 1 M

Formula

                            C1V1 = C2V2

                           V1 = C2V2 / C1

Process

                          V1 = (1 x 855) / 11.5

                          V1 = 855 / 11.5

                          V1 = 74.35 ml

c. because step up transformer steps up the input voltage i.e increases the input voltage  

the number of turns are greater on the secondary side of step up transformer  

transformer does not handle dc current