When simulating small molecules, others turn off the van der waal interaction between any atoms that are covalently bonded to one another, even though these interactions do exist in reality. (1) why do they do this? (hint: it has something to do with the time step). (2) how can they justify doing this? (hint: it has something to do with the differences between chemical bond types).

i think is conclusions.i think so

answerto predict;

answer: - first one is the correct answer. .

explanations: - potassium sulfide is and cobalt(ii) chloride is .

charge on k is +1, charge on s is -2, charge on co is +2 and charge on cl is -1.

in a double replacement reaction the ion exchange takes place. in general the reaction looks like:

if one of the product is insoluble as per solubility rules then a precipitate of it is formed.

when we mix the aqueous solutions of potassium sulfide and cobalt(ii) chloride then chloride ion goes with potassium ion and sulfide ion goes with cobalt ion and the balanced equation is written as:

k and cl has equal charges, similarly co and s has equal charges and hence no subscripts are used for the product side.

as per the solubility rules, cos is insoluble and so it's precipitate is formed.

looking at the given choices, first choice is correct.