Neutralizing an olympic size swimming pool is conceptually very similar to performaing a massive titration experiment. suppose a 700 thousand gallon swimming pool has a ph 9.33 which is a bit too high for swimming. calculate how many gallons of 10 m hci (strong acid) it will take to neutralize the swimming pool to ph = 7.

6,97x10⁻³ gallons

Explanation:

pH is defined as:

pH = -log [H⁺]

Thus, you need to have, in the end:

10⁻⁷ = [H⁺]

And you have, in the first:

= [H⁺]

The volume of swimming pool is:

700'000 galllons × = 2649787 L

Thus, the moles of H⁺ in the first and in the end are:

First:

× 2649787L = 1,24x10⁻³ moles

End:

× 2649787L = 0,265 moles

Thus, the moles of H⁺ you need to add are:

0,265 - 1,24x10⁻³ = 0,26376 moles

These moles comes from 10M HCl, thus, the volume in gallons you need to add are:

=

6,97x10⁻³ gallons

I hope it helps!

1.43 x 10^-11 j the guy commented the awnser just making sure u see it .

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