2. suppose that 21.37 ml of naoh is needed to titrate 10.00 ml of 0.1450 m h2so4 solution.
(a) write a balanced reaction equation for the acid-base neutralization.
(b) calculate the molarity of naoh based on the results of this titration.

0.1357 M

Explanation:

(a) The balanced reaction is shown below as:

(b) Moles of can be calculated as:

Or,

Given :

For :

Molarity = 0.1450 M

Volume = 10.00 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 10×10⁻³ L

Thus, moles of :

Moles of  = 0.00145 moles

From the reaction,

1 mole of react with 2 moles of NaOH

0.00145 mole of react with 2*0.00145 mole of NaOH

Moles of NaOH = 0.0029 moles

Volume = 21.37 mL = 21.37×10⁻³ L

Molarity = Moles / Volume = 0.0029 /  21.37×10⁻³  M = 0.1357 M

the seeing the electronic configuration we can say that the element is fluorine.

fluorine is the most electronegative element in the periodic table.

but by only seeing the configuration we cannot say about its reactivity because we don't know if its configuration after excitation or by addition of electrons.

but if not then, it is the lightest halogen and exists as a highly toxic pale yellow diatomic gas at standard conditions. as the most electronegative element, it is extremely reactive: almost all other elements, including some noble gases, form compounds with fluorine.