Question 8 of 8> 0 attempt 2 a chemist needs to determine the concentration of a sulfuric acid solution by titration with a standard sodium hydroxide solution. he has a 0.1284 m standard sodium hydroxide solution. he takes a 25.00 ml sample of the original acid solution and dilutes it to 250.0 ml. then, he takes a 10.00 ml sample of the dilute acid solution and titrates it with the standard solution. the endpoint was reached after the addition of 19.15 ml of the standard solution. what is the concentration of the original sulfuric acid solution? concentration: 025

12.29 M

Explanation:

H₂SO₄ + 2NaOH → 2Na⁺ + SO₄⁻² + 2H₂O

= 0.01229 mol H₂SO₄.

0.01229 mol H₂SO₄ / 0.010 L = 1.229 M

= 12.29 M

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j

a corroding iron, if that's one of your choices