Nitric oxide is formed in automobile exhaust when nitrogen and oxygen in air react at high temperatures. n2(g) + o2(g) ⇌ 2no(g)the equilibrium constant kp for the reaction is 0.14 at 1200 °c. if a container is charged with 0.175 atm of nitrogen and 0.127 atm of oxygen and the mixture is allowed to reach equilibrium, what will be the equilibrium partial pressure of oxygen? report your answer to three significant figures.

0.104 atm

Explanation:

The equilibrium constant based on the partial pressure (Kp) depends only on the gas substances. For a generic reaction aA(g) + bB(g) ⇄ cC(g) + dD(g), it can be calculated by:

, where pX represents the partial pressure of X. So, for the reaction given, let's do a equilibrium table:

N₂(g) + O₂(g) ⇄ 2NO(g)

0.175     0.127       0             Initial

-x            -x          +2x           Reacts (stoichiometry is 1:1:2)

0.175-x     0.127-x   2x         Equilibrium

4x² = 0.0031115 - 0.04228x + 0.14x²

3.86x² + 0.04228x - 0.0031115 = 0

Using Bhaskara:

Δ = (0.04228)² - 4x3.86x(-0.0031115)

Δ = 0.04983

x = (-0.04228 +/ √0.04983)/(2*3.86)

x must be positive, so let's calculate only for the positive:

x = 0.0234 atm

So, the equilibrium partial pressure of oxygen is

0.127 - 0.0234 = 0.104 atm

explanation:

venn diagram is pictorial representation with of circles showing the relation between two finite sets or things. the intersection part of two circles conveys the relation present in between those sets or things.

here in the venn diagram of sand and salt two circles represent sand and salt. but the area falling under the intersection of these circle represents the mixture of sand and salt.

so, in a venn diagram the mixture will be placed in a middle that is in between the intersection of two circles.