Determine what will happen if more hcl is added to the following reaction bicl3 (aq) + h 2 o (l) ⇌ biocl (s) + 2hcl (aq)
a. there will be no change.
b. less h2o will be produced.
c. more bicl3 will be produced.
d. less bicl3 will be produced.

C. more BiCl3 will be produced

Explanation:

Hello,

In this case, considering the Le Chatelier's principle regarding to the addition of a product, for this situation, HCl (hydrochloric acid), it is said the such addition will shift the reaction leftwards, it means, to the reactants bismuth (III) chloride and water,  in order to reattain equilibrium, therefore the answer related with the aforementioned explanation is C. more BiCl3 will be produced. Moreover, more water will be also produced.

Best regards.

because of all the things that happen around the us, many people get into arguments which sadly could get physical, but we should actually make a change for that.

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally