0.436 g of an unknown diprotic acid is dissolved in about 60 ml of water in a beaker. the solution is transferred to a 100.00 ml beaker. 25.00 ml of this solution is then transferred to an erlenmeyer flask for the titration. what mass of the diprotic acid is in the 25.00 ml that is transferred?

0.182 g

Explanation:

0.436 g of the acid was dissolved in 60 mL of water and then transferred into a 100.00 mL beaker. The volume still remains 60 mL.

25 mL was then transferred to Erlenmeyer flask for titration.

If 60 mL of the solution contains 0.436 g of the unknown diprotic acid, then 25 mL of the same solution would contain:

     0.436 x 25/60 = 0.182 g

Hence, the mass of the diprotic acid in the 25.00 mL of the solution is 0.182 g.